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17y^2+64y+60=0
a = 17; b = 64; c = +60;
Δ = b2-4ac
Δ = 642-4·17·60
Δ = 16
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{16}=4$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(64)-4}{2*17}=\frac{-68}{34} =-2 $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(64)+4}{2*17}=\frac{-60}{34} =-1+13/17 $
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